Iyengar Tkv wrote on your timeline.
For your problem on normal distribution: Standard normal variate z= (length - mew)/sigma. for x=4.4, z= (4.4-4.0)/ 0.2 = 2. Probabilitytha z >2 = (.5-.4722)= .0228. No of flies of the required type = 400*.0228 = eleven nearly. Hope you might have got this answer already. good luck. TKV Iyengar
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